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x^2+3.9x-3.9=0
a = 1; b = 3.9; c = -3.9;
Δ = b2-4ac
Δ = 3.92-4·1·(-3.9)
Δ = 30.81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.9)-\sqrt{30.81}}{2*1}=\frac{-3.9-\sqrt{30.81}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.9)+\sqrt{30.81}}{2*1}=\frac{-3.9+\sqrt{30.81}}{2} $
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